4g^2-13g+10=0

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Solution for 4g^2-13g+10=0 equation: 



4g^2-13g+10=0

a = 4; b = -13; c = +10;
Δ = b2-4ac
Δ = -132-4·4·10
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-3}{2*4}=\frac{10}{8}
=1+1/4
$


$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+3}{2*4}=\frac{16}{8}
=2
$

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